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When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are
\[x_1 = {-b + \sqrt{b^2-4ac} \over 2a}\]
\[x_2 = {-b - \sqrt{b^2-4ac} \over 2a} \notag\]
markdown:
When $$a \ne 0$$, there are two solutions to $$ax^2 + bx + c = 0$$ and they are
$$x_1 = {-b + \sqrt{b^2-4ac} \over 2a}$$
$$x_2 = {-b - \sqrt{b^2-4ac} \over...