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Mathjax When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \[x_1 = {-b + \sqrt{b^2-4ac} \over 2a}\] \[x_2 = {-b - \sqrt{b^2-4ac} \over 2a} \notag\] markdown: When $$a \ne 0$$, there are two solutions to $$ax^2 + bx + c = 0$$ and they are $$x_1 = {-b + \sqrt{b^2-4ac} \over 2a}$$ $$x_2 = {-b - \sqrt{b^2-4ac} \over...

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